20x^2-dx-d^2=0

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Solution for 20x^2-dx-d^2=0 equation: 


Simplifying
20x2 + -1dx + -1d2 = 0

Reorder the terms:
-1dx + -1d2 + 20x2 = 0

Solving
-1dx + -1d2 + 20x2 = 0

Solving for variable 'd'.

Factor a trinomial.
(-1d + -5x)(d + -4x) = 0


Subproblem 1
Set the factor '(-1d + -5x)' equal to zero and attempt to solve:

Simplifying
-1d + -5x = 0

Solving
-1d + -5x = 0

Move all terms containing d to the left, all other terms to the right.

Add '5x' to each side of the equation.
-1d + -5x + 5x = 0 + 5x

Combine like terms: -5x + 5x = 0
-1d + 0 = 0 + 5x
-1d = 0 + 5x
Remove the zero:
-1d = 5x

Divide each side by '-1'.
d = -5x

Simplifying
d = -5x

Subproblem 2
Set the factor '(d + -4x)' equal to zero and attempt to solve:

Simplifying
d + -4x = 0

Solving
d + -4x = 0

Move all terms containing d to the left, all other terms to the right.

Add '4x' to each side of the equation.
d + -4x + 4x = 0 + 4x

Combine like terms: -4x + 4x = 0
d + 0 = 0 + 4x
d = 0 + 4x
Remove the zero:
d = 4x

Simplifying
d = 4x
Solution
d = {-5x, 4x}

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